Math, asked by NickSingh1105, 1 year ago

Factorise this question fast!!!!
With explanation

Attachments:

Answers

Answered by siddhartharao77
0
Given : a^2 + b^2 - 2(ab - ac + bc)

= > a^2 + b^2 - 2ab + 2ac - 2bc

= > (a -b)^2 + 2c(a - b)

= > (a - b)(a - b + 2c).


Hope this helps!

siddhartharao77: :-)
NickSingh1105: But why?
siddhartharao77: Wt y?
NickSingh1105: Can you answer in detail with explanation the whole question
NickSingh1105: Pls
siddhartharao77: Thats Why i did
NickSingh1105: Ok then explain me what you did in the third step
NickSingh1105: Plsss
siddhartharao77: (a - b)^2 = a^2 + b^2 - 2ab and i have taken 2c common.
Answered by Anonymous
0
Hi,

Please see the attached file!


Thanks
Attachments:
Similar questions