Factorise this question fast!!!!
With explanation
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Given : a^2 + b^2 - 2(ab - ac + bc)
= > a^2 + b^2 - 2ab + 2ac - 2bc
= > (a -b)^2 + 2c(a - b)
= > (a - b)(a - b + 2c).
Hope this helps!
= > a^2 + b^2 - 2ab + 2ac - 2bc
= > (a -b)^2 + 2c(a - b)
= > (a - b)(a - b + 2c).
Hope this helps!
siddhartharao77:
:-)
But why?
Wt y?
Can you answer in detail with explanation the whole question
Pls
Thats Why i did
Ok then explain me what you did in the third step
Plsss
(a - b)^2 = a^2 + b^2 - 2ab and i have taken 2c common.
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Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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