Question

factorise this question plss 1. x³-3x²-9x-5​

Answer 1

$\huge \large \mathbf \green{solution}$

x³- 3x² - 9x - 5

= x³ + x²- 4x² - 4x - 5x - 5

= x²(x+1) - 4x(x+1) -5(x+1)

= (x+1)(x² - 4x - 5)

= (x+1)(x² - 5x + x - 5)

= (x+1)[x(x-5) + 1(x-5)]

= (x+1)[(x-5)(x+1)]

= (x+1)(x+1)(x-5)

=(x+1)²(x-5)