Factorise this using suitable identities
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Hi ,
54x^6y + 2x³y⁴
= 2x³y ( 27x³ + y³ )
= 2x³y [ (3x)³ + y³ ]
= 2x³y ( 3x + y ) [ (3x)² - 3x × y + y² ]
{ we know the algebraic identity
a³ + b³ = ( a + b )(a² - ab + b² ) }
= 2x³y( 3x + y ) ( 9x² -3xy + y² )
I hope this helps you ,
:)
54x^6y + 2x³y⁴
= 2x³y ( 27x³ + y³ )
= 2x³y [ (3x)³ + y³ ]
= 2x³y ( 3x + y ) [ (3x)² - 3x × y + y² ]
{ we know the algebraic identity
a³ + b³ = ( a + b )(a² - ab + b² ) }
= 2x³y( 3x + y ) ( 9x² -3xy + y² )
I hope this helps you ,
:)
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