Question

factorise through factorisation method
$2 {x}^{2} - x - 6 = 0$
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Answer 1

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Q:-factorise

${2x}^{2} - x - 6 = 0$

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------>>>>Here is your answer<<<<--------

$➾2 {x}^{2} - x - 6 = 0$

$➾2 {x}^{2} - 3x + 2x - 6 = 0$

$➾2x(x - 3) + 2(x - 3) = 0$

$➾(2x + 2)(x - 3) = 0$

$➾2x + 2 = 0$

$➾2x = - 2$

$➾x = - 1$✓

$➾x - 3 = 0$

$➾x = 3$✓

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Answer 2

Answer:

$2 {x}^{2} - x - 6 = 0$

$⟹2 {x}^{2} - (4 - 3)x - 6 = 0$

$⟹2 {x}^{2} - 4x + 3x - 6 = 0$

$⟹2x(x - 2) + 3(x - 2) = 0$

$⟹(x - 2)(2x + 3) = 0$

$so \:⟹ x - 2 = 0 \: and \: ⟹2x + 3 = 0$

$so \:⟹ x = 2 \: and \:⟹ x = \frac{ - 3}{2}$

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