Question

factorise to a square + b square
$2 {a}^{2} + {b}^{2} + 8 {c}^{2} - 2 \sqrt{2} ab + 4 \sqrt{2bc} - 8ac$
​

Answer 1

Answer:

a²-b²+2bc-c² =a² - (b² -2bc +c²)

                    =a² - (b-c)²

                    =(a-(b-c))(a+(b-c))  [ using identity a²-b² =(a-b)(a+b) ]

 

                   = (a-b+c)(a+b-c)

hence.,a²-b²+2bc - c²  = (a-b+c)(a+b-c)

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shreyajha19260 Ambitious

Step-by-step explanation:

I hope this will be helpful to you

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