Question

factorise (TUHOSA Shift) : (25m2 - 40mn + 16n2) - 49z2​

Answer 1

Answer:

(25m2-40mb+16n2)-49z2

=(25m2-2x5mx4n+16n2)-(7z)2

using (a-b)2=a2-2ab+b2 formula,

we have,

(5m-4n)2-(7z)2

using a2-b2=(a-b)(a+b) formula,

we have,

(5m-4n-(7z))(5m-4n+(7z))

(5m-4n-7z)(5m-4n+7z). (This is your answer).

Answer 2

Step-by-step explanation:

Using the identity (a

2

+b

2

−2ab)=(a−b)

2

We can write it as (25m

2

+16n

2

−40mn) as

=(5m)

2

+(4n)

2

−2×5m×4n

=(5m−4n)

2

Hence, the factors are(5m−4n)(5m−4n)