factorise using adenties
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Hey!!!!
we will use the identity ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca
Here We have,
x² + 9y² + 16z² + 12xy - 24yz - 16xz
=> We can write it as ( x + 3y - 4z )²
Hope this helps
we will use the identity ( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca
Here We have,
x² + 9y² + 16z² + 12xy - 24yz - 16xz
=> We can write it as ( x + 3y - 4z )²
Hope this helps
amit540:
thanks
always welcome
Answered by
1
(a+b+c)^2= a2+b2+c2+ab+bc+ac
(2x)^2+ (3y)^2+(-4z)^2+(2×2x×3y)+(2×3y×-4z)+(2×2x×-4z)
so,
(2x+3y-4z)^2
(2x)^2+ (3y)^2+(-4z)^2+(2×2x×3y)+(2×3y×-4z)+(2×2x×-4z)
so,
(2x+3y-4z)^2
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