Question

factorise using algebraic identities = 1-121x²​

Answer 1

Step-by-step explanation:

1=121x^2

1/121=x^2

x=√1/√121

x=1/11

Answer 2

Answer:

(1+11x)(1-11x)

Step-by-step explanation:

$1 = ( {1}^{2} ) \\ 121 {x}^{2} = (11x) {}^{2} \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {1}^{2} - 11 {x}^{2} = (1 + 11x)(1 - 11x)$

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