Question

factorise using appreciate identies (3a-7b-c)2​

Answer 1

Answer:

3a−7b+4c)

2

=(3a)

2

+(−7b)

2

+(4c)

2

+2(3a)(−7b)+2(−7b)(4c)+2(4c)(3a)

=9a

2

+49b

2

+16c

2

−42ab−56bc+24ca