Math, asked by deepmathematician, 11 months ago

factorise using appropriate identity x^2-y^2/100​

Answers

Answered by Anonymous
7

GOOD MORNING!

( - )/100

( x/10)² - (y/10)²

{ ( x/10 ) + (y/10) } ×{ (x/10) - (y/10)}

Becoz - = ( a + b ) × ( a - b )

Answered by brunoconti
4

Answer:

Step-by-step explanation:

a^2 - b^2 = (a - b)(a + b)

x^2 - y^2 / 100 = (x - y / 10)(x + y / 10)

Similar questions