factorise using appropriate identity x^2-y^2/100
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GOOD MORNING!
(x² - y²)/100
( x/10)² - (y/10)²
{ ( x/10 ) + (y/10) } ×{ (x/10) - (y/10)}
Becoz a² - b² = ( a + b ) × ( a - b )
Answered by
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Answer:
Step-by-step explanation:
a^2 - b^2 = (a - b)(a + b)
x^2 - y^2 / 100 = (x - y / 10)(x + y / 10)
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