factorise using factor theorem 3x³-x²+3x+1
Answers
Answered by
3
Answer:
(3x-1)(x^2+1)
Step-by-step explanation:
3x^3 - x^2 +3x + 1, set it = 0
3x^3 - x^2 +3x + 1 = 0
=3x^3 + 3x - x^2 +1 = 0
=3x(x^2+1) - (x^2 + 1) = 0
=(3x-1)(x^2+1) "This Is By normal factorization"
Similar questions