Question

factorise using factor theorem 3x³-x²+3x+1​

Answer 1

Answer:

(3x-1)(x^2+1)

Step-by-step explanation:

3x^3 - x^2 +3x + 1, set it = 0

3x^3 - x^2 +3x + 1 = 0

=3x^3 + 3x - x^2 +1 = 0

=3x(x^2+1) - (x^2 + 1) = 0

=(3x-1)(x^2+1) "This Is By normal factorization"