Factorise using factor theorem
6x^3-7x^2-8x+5
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6x^3-7x^2-8x+5
=(x+1) (6x^2-13x+5)
=(x+1) [(6x^2-3x-10x+5)]
=(x+1) [3x(2x-1)-5(2x-1)]
=(x+1) (2x-1) (3x-5)
=(x+1) (6x^2-13x+5)
=(x+1) [(6x^2-3x-10x+5)]
=(x+1) [3x(2x-1)-5(2x-1)]
=(x+1) (2x-1) (3x-5)
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