Question

factorise using factor theorem
x^3-2x^2-5x+6​

Answer 1

Answer:

$= > (x - 1)(x - 3)(x + 2)$

Step by step explanation:

$p(x) = {x}^{3} - 2 {x}^{2} - 5x + 6$

$p(1) = 0$

Hence taking x-1 as common

$= > (x - 1)( {x}^{2} - x - 6)$

$= > ( {x}^{} - 1)( {x}^{2} - 3x + 2x - 6)$

$= > (x - 1)(x(x - 3) + 2(x - 3) )$

$= > (x - 1)(x - 3)(x + 2)$

hope it helps ♥️