Factorise
using
factors theorem,
x^3 + 4x² + 5x +2
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Answered by
3
Answer:
To find the other roots we need to divide #x^3+4x^2+5x+2# by #x+1#:
#(x^3+4x^2+5x+2)/(x+1)#
=#x^2+(3x^2+5x+2)/(x+1)#
=#x^2+3x+ (2x+2)/(x+1)#
=#x^2+3x+2#
Step-by-step explanation:
Now we can apply thye general formula for a second degree polynom:
#x=(-3+-sqrt(3^2-4*2))/2#
#x=(-3+-sqrt(1))/2#
#x=(-3+-1)/2#
#x=(-4)/2 or x=(-2)/2#
#x=-2 or x=-1#
So the factorization will be
the product of (x-roots) or
#(x+1)^2(x+2)#
Answered by
1
Answer:
it is different method of solving the cubic polynomial but keep In mind that this method is applicable only there is x^3
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