factorise using HCF abc+ aby+abz
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Answered by
7
Answer:
ab is common in it
so
ab is HCF of abc+ aby+ abz
ab{c+ y+ z}
Answered by
0
ab(c+y+z)
Step-by-step explanation:
common factors=ab
ab is hcf of abc+aby+abz
ab(c+y+z)
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