factorise using identities
1) 16 a^4b + 2ab^4
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16 a⁴b + 2ab⁴
= 2ab(8a³+b3)
= 2ab{(2a)³+(b)³}
= 2ab(2a+b){(2a)²-2a.b+b²)}
= 2ab(2a+b)(4a²-2ab+b²)
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⭐ refer to the attachment ⭐
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