Question

Factorise using identities:-

1) a²+6a+9

Answer 1

a^2 +6a + 9

= a^2+3a+3a+9

= a(a+3)+3(a+3)

= (a+3)(a+3)

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Answer 2

a² + 6a + 9 = (a + 3)(a + 3)

Given :

The expression a² + 6a + 9

To find :

To factorise using identity

Identity Used :

(a + b)² = a² + 2ab + b²

Solution :

Step 1 of 2 :

Write down the given expression

Here the given expression is a² + 6a + 9

Step 2 of 2 :

Factorise the expression

$\displaystyle \sf{ {a}^{2} + 6a + 9 }$

$\displaystyle \sf{ = {a}^{2} + 2.a.3 + {(3)}^{2} }$

$\displaystyle \sf = {(a + 3)}^{2}\: \: \: \bigg[ \: \because \: {a}^{2} + 2ab + {b}^{2} = {(a + b)}^{2} \bigg]$

$\displaystyle \sf{ = (a + 3)(a + 3) }$

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Learn more from Brainly :-

$1.$ Find factorisation x⁴+2x²+9

https://brainly.in/question/16207943

2. Factorize: x2 – 9y2 + 2x + 1

https://brainly.in/question/50568785

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