Factorise using identities 10x2 - 14x3 + 18x4
Answers
Answer:
Changes made to your input should not affect the solution:
(1): "x4" was replaced by "x^4". 2 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
((10•(x2))-(14•(x3)))+(2•32x4)
STEP
2
:
Equation at the end of step
2
:
((10 • (x2)) - (2•7x3)) + (2•32x4)
STEP
3
:
Equation at the end of step
3
:
((2•5x2) - (2•7x3)) + (2•32x4)
STEP
4
:
STEP
5
:
Pulling out like terms
5.1 Pull out like factors :
18x4 - 14x3 + 10x2 = 2x2 • (9x2 - 7x + 5)
Trying to factor by splitting the middle term
5.2 Factoring 9x2 - 7x + 5
The first term is, 9x2 its coefficient is 9 .
The middle term is, -7x its coefficient is -7 .
The last term, "the constant", is +5
Step-1 : Multiply the coefficient of the first term by the constant 9 • 5 = 45
Step-2 : Find two factors of 45 whose sum equals the coefficient of the middle term, which is -7 .
-45 + -1 = -46
-15 + -3 = -18
-9 + -5 = -14
-5 + -9 = -14
-3 + -15 = -18
-1 + -45 = -46
1 + 45 = 46
3 + 15 = 18
5 + 9 = 14
9 + 5 = 14
15 + 3 = 18
45 + 1 = 46
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
2x2 • (9x2 - 7x + 5)
Answer:
50
Step-by-step explanation:
10×2=20-14×3=42+18×4=72
so 20-42+72=50.