Question

Factorise using identities : 4x^2-44xy+121y^2
Pls give step by step answer​

Answer 1

Explanation:

$4x^2 -44xy+121y^2$

$=(2x)^2 - 2(2x)(11y)+(11y)^2$

$=(2x-11y)^2$ [because $a^2 - 2ab + b^2 = (a-b)^2]$

$=(2x-11y)(2x-11y)$

Answer: (2x-11y)(2x-11y)

I hope this helps. :D

Answer 2

Answer:

STEP

1

:

Equation at the end of step 1

((4 • (x2)) + 44xy) + 112y2

STEP

2

:

Equation at the end of step

2

:

(22x2 + 44xy) + 112y2

STEP

3

:

Trying to factor a multi variable polynomial

3.1 Factoring 4x2 + 44xy + 121y2

Try to factor this multi-variable trinomial using trial and error

Found a factorization : (2x + 11y)•(2x + 11y)

Detecting a perfect square :

3.2 4x2 +44xy +121y2 is a perfect square

It factors into (2x+11y)•(2x+11y)

which is another way of writing (2x+11y)2

How to recognize a perfect square trinomial:

• It has three terms

• Two of its terms are perfect squares themselves

• The remaining term is twice the product of the square roots of the other two terms

Final result :

(2x + 11y)

I hope it was right and mark me on brainliest!!!