factorise using identities 4x²-4x-3
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Answered by
1
Step-by-step explanation:
4x^2-4x-3
4x^2 - 4x + 3x -3
4x(x-1) + 3(x-1)
(x-1)(4x+3)
first try to urself _/\_
Answered by
0
Answer:
(2x-2)^2-7 first we check coefficients of X2 then coefficient of X in that way we can factorise
(2x-2-✓7)(2x-2+✓7) is the answer
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