Question

Factorise Using identities
- 64a3-12a+ 48a square​

Answer 1

Answer:

→1-64a³-12a+48a²

=(1)³-(4a)³-3(1)²(4a)+3(1)(4a)²

This is in the form of a³-b³-3a²b+3ab².

So,a³-b³-3a²b+3ab² = (a-b)³

Here,

a=1,b=4a

So,

(1)³-(4a)³-3(1)²(4a)+3(1)(4a)² = (1-4a)³

So,answer is (1-4a)³

Step-by-step explanation: