Question

Factorise using identities

Answer 1

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Let's simplify the given equation into cube roots of their respective number:

${( \sqrt{3}a) }^{3} + {(2b)}^{3} - {(2b)}^{3} - 18 \sqrt{3} abc$

Now, as we have the identity:

${(a + b + c)}^{3} = {a}^{2} + {b}^{3} +{c}^{2} + 3abc$

Therefore, the equation we found will be:

${(( \sqrt{3} a) + (2b) - (3c))}^{3} = {( \sqrt{3}a) }^{3} + {(2b)}^{3} - {(2b)}^{3} - 18 \sqrt{3} abc$

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Answer 2

Answer:

Identity = x^3 + y^3 + z^3  - 3xyz = (x+y+z) ( xy^2 + yz^2  + zx^2  -xy -yz -zx)

For Step-by-step explanation plz refer the given attachment :

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