factorise using identities 8x²-(2x-y)³
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Answer: It is in the form of :- a³-b³,
(2x)³-(2x-y)³ = (2x-2x+y) {4x²+(2x-y)² +2x ×( 2x-y)}
= y(4x²+4x² + y²-4xy +4x²-2xy)
= y(12x²-6xy +y²)
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