Question

Factorise using identities :

${63a}^{2} - {112b}^{2}$
${(l + m)}^{2} - {(l - m)}^{2}$
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Answer 1

Answer:

(7*9)a²-(7*16)b²

7(9a²-16b²)

7(3a)²-(4a)²

7(3a+4b)(3a-4a)

Answer 2

Answer;

{63a}^{2} - {112b}^{2}63a2−112b2

⇒63a2−112b2

factorize = taking common 7, then,

7 [9a2−16b2]

[(3a)2−(4b)2]

[(3a+4b)(3a−4b)]

[a2−b2=(a+b)(a−b)]

(l+m)2−(l−m)2

( l + m)2 - (l - m)2

= [ l +m + l - m][l + m - l + m]

= 2l x 2m = 4lm

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