Math, asked by drarchanadeore, 3 months ago

factorise using identity- 100x^2-140xy+49y^2​

Answers

Answered by Anonymous
6

Step-by-step explanation:

Factoring 100x2 - 140xy + 49y2

Factoring 100x2 - 140xy + 49y2 Try to factor this multi-variable trinomial using trial and error

Factoring 100x2 - 140xy + 49y2 Try to factor this multi-variable trinomial using trial and error Found a factorization : (10x - 7y)•(10x - 7y)

Answered by tennetiraj86
1

Step-by-step explanation:

Given:-

100x^2-140xy+49y^2

To find :-

factorise using identity- 100x^2-140xy+49y^2

Solution:-

Given expression is 100x²-140xy+49y²

=>10²x²-140xy+7²y²

=>(10x)²-2(10x)(7y)+(7y)²

It is in the form of a²-2ab+b²

Here , a=10x

and b=7y

We know that

a²-2ab+b²=(a-b)²

=>(10x)²-2(10x)(7y)+(7y)²

=>(10x-7y)²

=>(10x-7y)(10x-7y)

Answer:-

100x²-140xy+49y² = (10x-7y)(10x-7y)

Used Identity:-

  • (a-b)²=a²-2ab+b²
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