Question

factorise using identity 11m^2 - 54m + 63​

Answer 1

Step-by-step explanation:

$\tt \: 11m^{2}-54m+63=0$

$\\ \tt \:m=\frac{-\left(-54\right)±\sqrt{\left(-54\right)^{2}-4\times 11\times 63}}{2\times 11}$

$\\ \tt m=\frac{-\left(-54\right)±\sqrt{2916-44\times 63}}{2\times 11}$

$\\ \tt \: m=\frac{-\left(-54\right)±\sqrt{144}}{2\times 11}$

$\\ \tt \: m=\frac{-\left(-54\right)±12}{2\times 11}$

$\\ \tt \: m=\frac{54±12}{22}$

$\\ \tt \: m=\frac{54 + 12}{22} \: \: \: and \: \: \: m=\frac{54 - 12}{22}$

$\\ \tt m = \frac{66}{22} \: \: \:and \: \: \: m = \frac{42}{22}$

$\\ \boxed{ \red{ \tt \: m = 3 \: \: \: and \: \: \: m = \frac{21}{11} }}$

Answer 2

11x2 – 54x + 63

The coefficient of x2 is 11 The coefficient of x is -54 Constant term is 63 So, we express the middle term -54x as -33x – 21x 11x2 – 54x + 63

= 11x2 – 33x – 21x – 6

= 11x (x – 3) – 21 (x – 3)

= (11x – 21) (x – 3)

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