Question

Factorise using identity
(3x+1)²​

Answer 1

Step-by-step explanation:

(4x−2y−3z)

2

We know that (x+y+z)

2

=x

2

+y

2

+z

2

+2xy+2yz+2xz

Here x=4x, y=-2y and z=-3z we get

(4x−2y−3z)

2

=(4x)

2

+(−2y)

2

+(−3z)

2

+2(4x)(−2y)+2(−2y)(−3z)+2(4x)(−3z)

=16x

2

+4y

2

+9z

2

−16xy+12xy−24xz

Answer 2

Answer:

(3x+1)²​ = 9x²+6x+1

PLEASE BRAINLIEST MY ANSWER

Step-by-step explanation:

We know that the identity is-

(ax+b)² = (ax)²+2axb+b²

Now,

(3x+1)²​ = (3x)²+2*3x**1+1²

(3x+1)²​ = 9x²+6x+1

I HOP THIS ANS IS HELPFUL FOR YOU