Question

Factorise using identity 4y^2-81 ​

Answer 1

Step-by-step explanation:

4y²-81

(2y)²-9²

(2y-9)(2y+9)

Answer 2

Answer:

We can factor this as a "difference of squares." Remember that a2 - b2 = (a + b)(a - b) . So....

4y2 - 81 = (2y)2 - 92 = ( 2y + 9 )( 2y - 9 )