. Factorise using identity 64n square – 16n + 1
Answers
Answer:
Step-by-step explanation:
Factoring 64n2-16n+1
The first term is, 64n2 its coefficient is 64 .
The middle term is, -16n its coefficient is -16 .
The last term, "the constant", is +1
Step-1 : Multiply the coefficient of the first term by the constant 64 • 1 = 64
Step-2 : Find two factors of 64 whose sum equals the coefficient of the middle term, which is -16 .
-64 + -1 = -65
-32 + -2 = -34
-16 + -4 = -20
-8 + -8 = -16 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -8 and -8
64n2 - 8n - 8n - 1
Step-4 : Add up the first 2 terms, pulling out like factors :
8n • (8n-1)
Add up the last 2 terms, pulling out common factors :
1 • (8n-1)
Step-5 : Add up the four terms of step 4 :
(8n-1) • (8n-1) = (8n-1) square
Which is the desired factorization
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Answer:
(8n-1)²
Step-by-step explanation:
This Factrozation are based on the identity of (a-b)²