factorise using identity
(7a+2b)2
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Answer:
49a²+4b²+28ab
Step-by-step explanation:
(7a+2b)² can be factorized using the identity (a+b)²=a²+2ab+b²
here, a = 7a and b = 2b
Using identity,
(7a+2b)²= (7a)²+(2b)²+2×7a×2b
= 49a²+4b²+28ab
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