Question

Factorise using identity - 8x^3 -27y^3 + 64z^3+72xyz




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Answer 1

Answer:

-12

Step-by-step explanation:

x^3 + y^3 + z^3 -3xyz=(x + y + z)(2x + 2y + 2z -xy - yz - zx)

(-2)^3+(-3)^3+(4)^3=(-2-3+4)(-4-6+8-6+12+8)

                             =(-1)(12)

                             =-12

hope this is helpful

_a1eef_ @ ig