Factorise using identity 9x 2 -24xy+16y 2
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9x²-24xy+16y²
(3x)²-2*3x*(-4y)+(4y)²
This is in the form of (a-b)²
a²-2ab+b²= (a-b)²
(3x-4y)(3x-4y)
(3x-4y)²
(3x)²-2*3x*(-4y)+(4y)²
This is in the form of (a-b)²
a²-2ab+b²= (a-b)²
(3x-4y)(3x-4y)
(3x-4y)²
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Answer:
9x²-24xy+16y²
(3x)²-2*3x*(-4y)+(4y)²
This is in the form of (a-b)²
a²-2ab+b²= (a-b)²
(3x-4y)(3x-4y)
(3x-4y)²
(3x-4y) (3x-4y)- This is the irreducable form
Step-by-step explanation:
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