Question

factorise using identity a^4 - 16​

Answer 1

Answer:

$(a^{2} )^{2} - 4^{2} =\\(a^{2} - 4)(a^{2} + 4)\\Factorise \\a^{2} - 2^{2} = (a-2)(a+2)\\thus\\(a - 2)(a + 2)(a^{2} + 4)$

Step-by-step explanation:

Answer 2

Answer:

a^4 - 16

a^4 - 2^4

(a^2 + 2^2) (a^2 - 2^2)

thanks a lot