Question

Factorise using identity
I. (2x-y-z)^2
Pls solve this I really need it...

Answer 1

Step-by-step explanation:

$1) \: (2x - y - z) ^{2}$

$= (2x) ^{2} + ( - y) ^{2} + ( - z) ^{2} - 2(2x)( - y) + 2( - y)( - z) +2 ( - z)(2x)$

$= 4 {x}^{2} + {y}^{2} + {z}^{2} - 4xy + 2yz - 4zx$