Math, asked by minasingh09ak, 9 months ago

factorise using identity
n2-8​

Answers

Answered by anshika799
0

Answer:

2n - 8

2(n-4)

...............

Answered by Anonymous
3

Answer:

 {a}^{2}  -  {b}^{2}  = (a - b)(a + b) \\  {n}^{2}  - 8 \\  = (n + 4)(  n- 4)

Please mark my answer as brainlist

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