Question

Factorise- using identity
$4x^{2} -4y^{2} +16z^{2} -16xz$

who will give correct answer will mark as brainliest with full explanation only.

Answer 1

$\blue{ \: \: \: \: \: \: \: 4x^{2} -4y^{2} +16z^{2} -16xz}$

• By taking the common factor out, the is..

$= > \blue{4( {x}^{2} - {y}^{2} + 4z^{2} - 4xz)}$

• By factoring the equation by using

{a² - 2ab + b² = (a+b)²} the value is....

$= > \: \: \: \: \: \: \: \blue{4((x - 2z)^{2} - {y}^{2} ) }$

• By factoring the equation by using

{a²-b² = (a-b)(a+b)} the value is....

$= > \blue{ 4(x - 2z - y)(x - 2z + y)}$