Question

factorise using identity (x+2y)^2-4(2x-4y)^2​

Answer 1

Step-by-step explanation:

(x+2y)²-4(2x-4y)²

= (x+2y)²-[2(2x-4y)]²

= [(x+2y)+2(2x-4y)] [(x+2y)-2(2x-4y)]

= [x+2y+4x-8y] [x+2y-4x+8y]

= (5x-6y) (10y-3x)

We are using the identity a²-b² = (a+b)(a-b)

Here, a = (x+2y) & b = 2(2x-4y)