factorise using identity
x^3 - x
So, what will be the answer?
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2
x³-x (taking x common)
x(x²-1)
now, a²-b² = (a+b)(a-b)
x(x+1)(x-1)
hence, factorised...
x(x²-1)
now, a²-b² = (a+b)(a-b)
x(x+1)(x-1)
hence, factorised...
Answered by
7
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