Question

factorise using middle term splitting.
(a) m^2-7m-30​

Answer 1

Answer:

$m {}^{2} - 7m - 30$

$= m {}^{2} - (10 - 3)m - 30$

$= m {}^{2} - 10m + 3m - 30$

$= m(m - 10) + 3(m - 10)$

$= (m - 10)(m + 3)$

Step-by-step explanation:

(m-10)(m+3) will be the required solution.

Thanks.

Answer 2

Answer:

(m - 10)(m + 3)

Step-by-step explanation:

Splitting the middle term such that its the sum of factors of the product of the other two terms(extremes).

• product of the extremes = - 30

• suitable factors = -10 and 3

• sum of these factors = -10 + 3 = -7

m² - 7m - 30

• writing 7m as -10m + 3m

m² - 10m + 3m - 30

• taking m and 3 common

m(m - 10) + 3(m - 10)

• taking (m - 10) common

$\boxed{(m + 3)(m - 10)}$

which is the Required factor form

                                     

Hope this helps!