Question

factorise using repraugins

Answer 1

3xy-4y-3x+4
3xy-3x-4y+4
3x(y-1)-4(y-1)
(y-1)(3x-4)


12x-8+3xy-2y
12x+3xy-8-2y
3x(4+y)-2(4+y)
(4+y)(3x-2)

x²+xy+9x+9y
x²+9x+xy+9y
x(x+9)+y(x+9)
(x+9)(x+y)

Answer 2

3xy-4y-3x+4
3xy-3x- 4y+4
3x (y-1) - 4 (y-1)
y-1 or 3x-4 =0
y=1 or x=4/3 =0

and

12x-8+3xy-2y
12x+3xy-8-2y
3x (4+y) -2 (4+y)
4+y or 3x-2 =0
y=-4 or x= 2/3 =0

and

x square +xy+9x+9y
x (x+y) +9 (x+y)
x+9 or x+y =0
x=-9 or y= x =0

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