Factorise using suitable groupings:
1)abc-ab-c+1
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Answer:
abc-ab-c+1
=>ab(c-1)-1(c-1)
=>(ab-1)(c-1)
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Answered by
0
ab=1 c=1
Step-by-step explanation:
ab(c-1)-1(c-1)
(ab-1) (c-1)
ab=1 c=1
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