Question

Factorise using suitable identities 116x² + 64x⁴ I will brainlist if right answer

Answer 1

=4x^2(29+16x^2)

This can not be factorise further.

REASON

Let f(x)=4x^2(29+16x^2)

According to remainder theorem,

When x=a(let) and f(a)=0

the x-ais the factor of f(x).

But in this function,

any value of x will give answer greater than 0(except 0, which will give x is factor of f(x) which is already taken common)