factorise using suitable identities 49x²-140xy+100y²
Answers
Answered by
3
The answer is (7x-10y)²
The identity used here is (a²+b²-2ab)=(a-b)²
The identity used here is (a²+b²-2ab)=(a-b)²
Answered by
4
using a²-2ab+b²
(7x)²-2(7x)(10y)+(10y)²
(7x-10y)²=(7y-10y)(7y-10y)
(7x)²-2(7x)(10y)+(10y)²
(7x-10y)²=(7y-10y)(7y-10y)
Similar questions