Question

factorise using suitable identities 4ysquare-4y+1​

Answer 1

Answer:

(2y-1)(2y-1)

Step-by-step explanation:

4y^2-4y+1

=(2y)^2-2.2y.1+1^2

=(2y--1)^2. [ as, (a-b)2=a^2-2ab+b^2]

=(2y-1)(2y-1)