Question

factorise using suitable identities 9 a square + 12 + 4

Answer 1

Hey mate, here is your answer -:)

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$9 {a}^{2} + 12a + 4 \\ {9a}^{2} + (6 + 6)a + 4 \\ {9a}^{2} + 6a + 6a + 4 \\ 3a(3a + 2) + 2(3a + 2) \\ (3a + 2)(3a + 2)$

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HOPE it helps to you!!!

Answer 2

Hey Friends,
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${9a}^{2} + 12a + 4$
$= {9a}^{2} + 6a + 6a + 4$
$= 3a(3a + 2) + 2(3a + 2)$
$= (3a + 2)(3a + 2)$
$= {(3a + 2)}^{2}$
or
${(3a)}^{2} + 2 \times 2 \times 3a + {2}^{2}$
$= {(3a + 2)}^{2}$


HOPE IT'S HELP YOU!!!!
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