Factorise using suitable identities 9 a square + 12 + 4
shadowsabers03:
Is it 12a or 4a?
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0
Hey Friends,
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{9a}^{2} + 12a + 4
= {9a}^{2} + 6a + 6a + 4
= 3a(3a + 2) + 2(3a + 2)
= (3a + 2)(3a + 2)
= {(3a + 2)}^{2}
or
{(3a)}^{2} + 2 \times 2 \times 3a + {2}^{2}
= {(3a + 2)}^{2}
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Answered by
1
Answer:
{9a}^{2} + 12a + 4
= {9a}^{2} + 6a + 6a + 4
= 3a(3a + 2) + 2(3a + 2)
= (3a + 2)(3a + 2)
= {(3a + 2)}^{2}
or
{(3a)}^{2} + 2 \times 2 \times 3a + {2}^{2}
= {(3a + 2)}^{2}
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