Question

factorise using suitable identities:
p²–4pq+4q²–4r²
plzzz give the correct solution...​

Answer 1

Answer:

(P2 - 4pq + 4q2) -4r2

identity :( a-b) 2= (A2 - 2ab + b2 )

=(p-2q)2 - 4r2

=(p-2q)2 - (2r)2

identity : (a)2 - (b)2 = (a+b) (a-b)

=(p-2q+2r)(p-2q-2r)