Math, asked by adityasingh913, 7 months ago

Factorise using suitable identity 16a+54ab³

Answers

Answered by Imblank

1

Answer:

16a+54ab³

2a(8+27b³)

2a{(2)³+(3b)³}

2a(2+3b)(2²+2.3b+3²b²)

2a(2+3b)(4+6b+9b²)

(4a+6b)(4+6b+9b²)

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