Question

Factorise using suitable identity (2x−3y)^3 +(3y−4z)^3 +(4z−2x)^3

Answer 1

Step-by-step explanation:

using (a-b)^3 = a^3-3a^2b+3ab^2-b^3

(8x^3-36x^2y+54xy^2-27y^3) + (27y^3-108y^2z+144yz^2-64z^3) + (64z^3-96xz^2+48x^2z-8x^3)

cancelling the opposites

( -36x^2y+54xy^2-108y^2z+144yz^2-96xz^2+48x^2z )