Factorise using suitable identity: =8p³+1 is the question. Please answer to this question.. . I will mark the answered person as branliest
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Answer:
(2p-1)(4p²+2p+1)
Step-by-step explanation:
8p³ + 1
= (2p)³ +(1)³ [using a³+b³ = (a-b)(a²+ab+b²)]
= (2p-1)[(2p)²+ 2p×1 + (1)²]
= (2p-1)(4p²+2p+1)
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